Wednesday 15 October 2014

IGCSE Further Algebra

Worksheet

1. Solve Inequality, download here
2. Solve simultaneous linear equations, download here
3. Find inverse formula, download here
4. Factorise quadratic expression download here
5. Product of prime factor download here
6. Composite Functions download here

1. SOLVING INEQUALITY

After studying this section, you will be able to:

  • solve inequalities with one variable
  • solve inequalities with two variables
Inequalities in one variable
NOTE:
When working with a double inequalities start by solving the two inequalities. An integer is any whole number, positive negative or zero.

When solving inequalities do not forget that multiplying or dividing by a negative number reverses the inequality sign:
−x > 3, becomes x < −3 (multiplying by −1).
Inequalities in two variables
NOTE:Remember an equation in the form y = 2x – 1 has gradient 2 and y-intercept (where it crosses the y-axis) of –1, 
in other words y = (gradient) x + (y -intercept)
PROGRESS TEST


2. Simultaneous Equations

After studying this section, you will be able to:

  • solve simultaneous inequalities with substitution
  • solve simultaneous inequalities with elimination
  • solve simultaneous inequalities with graph
1st method : Substitution
This method is called solution by substitution.
It involves what it says − substitution − using one of the equations to get an expression of the form ‘y = …’ or ‘x = …’ and substituting this into the other equation. This gives an equation with just one unknown, which can be solved in the usual way. This value is then substituted in one or other of the original equations, giving an equation with one unknown.
NOTE:With this method you need to take particular care with your algebra. Should your solutions be ‘strange’ fractions such as 9/13 the chances are you’ve  made a slip − check your algebra.
NOTE:
  • It is a good idea to label each equation. It helps you explain what you are doing − and may gain you method marks.
  • This value of x can be substituted into equation [1] or [2], or into the expression for y: y = 2x − 1.
  • Choose the one that is easiest!
  • As a check, substitute the values back into each of the two starting equations.
The second method is called solution by elimination.
NOTE:The method is not quite as hard as it first seems, but it helps if you know why it works.
It works because of two properties of equations:
  • Multiplying (or dividing) the expression on each side by the same number does not alter the equation.
  • Adding two equations produces another valid equation:
    e.g. 2x = x + 10 (x = 10) and x − 3 = 7 (x also = 10).
    Adding the equations gives 2x + x − 3 = x + 10 + 7 (x also = 10).
The object is to manipulate the two equations so that, when combined, either the x term or the y term is eliminated (hence the name) − the resulting equation with just one unknown can then be solved:
Solving simultaneous linear equations using straight line graphs
NOTE:
Because the graphs of 2y + x = 8 and y + 1 = 2x are straight lines, they are called linear equations.
Drawing two straight line graphs to solve simultaneous
equations also works the other way round − solving the two simultaneous equations algebraically gives the coordinates of the point of intersection of the two straight line graphs of the two simultaneous equations.
PROGRESS CHECK

Read more at http://revisionworld.com/gcse-revision/maths/number-and-algebra/algebra/simultaneous-linear-equations#PXoUA6W1EWFLCkKX.99
This method is called solution by substitution.
It involves what it says − substitution − using one of the equations to get an expression of the form ‘y = …’ or ‘x = …’ and substituting this into the other equation. This gives an equation with just one unknown, which can be solved in the usual way. This value is then substituted in one or other of the original equations, giving an equation with one unknown.
NOTE:With this method you need to take particular care with your algebra. Should your solutions be ‘strange’ fractions such as 9/13 the chances are you’ve  made a slip − check your algebra.
NOTE:
  • It is a good idea to label each equation. It helps you explain what you are doing − and may gain you method marks.
  • This value of x can be substituted into equation [1] or [2], or into the expression for y: y = 2x − 1.
  • Choose the one that is easiest!
  • As a check, substitute the values back into each of the two starting equations.
The second method is called solution by elimination.
NOTE:The method is not quite as hard as it first seems, but it helps if you know why it works.
It works because of two properties of equations:
  • Multiplying (or dividing) the expression on each side by the same number does not alter the equation.
  • Adding two equations produces another valid equation:
    e.g. 2x = x + 10 (x = 10) and x − 3 = 7 (x also = 10).
    Adding the equations gives 2x + x − 3 = x + 10 + 7 (x also = 10).
The object is to manipulate the two equations so that, when combined, either the x term or the y term is eliminated (hence the name) − the resulting equation with just one unknown can then be solved:
Solving simultaneous linear equations using straight line graphs
NOTE:
Because the graphs of 2y + x = 8 and y + 1 = 2x are straight lines, they are called linear equations.
Drawing two straight line graphs to solve simultaneous
equations also works the other way round − solving the two simultaneous equations algebraically gives the coordinates of the point of intersection of the two straight line graphs of the two simultaneous equations.
PROGRESS CHECK

Read more at http://revisionworld.com/gcse-revision/maths/number-and-algebra/algebra/simultaneous-linear-equations#PXoUA6W1EWFLCkKX.99

2nd Method : Elimination

3rd Method : Graph



Progress Test

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